I was just curious as to how you calculate the displacement of an engine. I know that it is determined by the stroke and the bore, but what is the actually mathematical equation that I can use to arrive at the final displacement number if I know what the stroke and bore of an engine is? Also without knowing the stoke and the bore of an engine can I use the liter size to determine it? for example is a 5.7L always equal to 345 and is a 7.0L always equal to 427?

 

displacement is: (Number of cylinders) * 3.14159x(Bore/2)^2 * Stroke:

(3.14159 is pi) and "*means multiply and "^" means to the power of:

My C5R has 8 cylinders and a bore of 4.125 inches and a stroke of 4 inches, so:

8 x 3.14159 x (4.125/2)^2 x 4.0 = 427.6489 cubic inches.

 

lee, say that again,i will have to go back to school to figure that math out,,,,,,,woooooooo man,,,, LOL

 

Corvette King. I'm curious what rear tires you run on the Nova?

 

A liter is always 61 cubic inches. Thus, 427 cubic inches is exactly 7 liters --
427/61 = 7.0 liters
366/61 = 6.0 litters
346/61 = 5.7 liters
305/61 = 5 liters
281/61 = 4.6 (Ford Mustang V8 or GM Northstar V8)
256/61 = 4.2 liters (Jaguar, either the straight six in the XKE or V8 in the much newer XJ)
220/61 = 3.6 liters (my Porsche)
183/61 = 3.0 liters
122/61 = 2.0 liters

 

hay whats up lee just got back fom my trip. was great.the tire size i run are goodyear 32x16.0-15 on a 14 inch rim weld pro stars. i have tried every tire out there and i like goodyear the best a little more money but they are great . what are you running for rubber

 

I run BFG drag radials on the rear of both cars on the street, wish Goodyear made a 345x18 tire in my size, and we run Mickey Thmpson slicks on the Camaro at the track.

 

Bore Squared X Stroke X .7854 X The number of cylinders = Cubic Inch Displacement.